Lesson 16 / Theory and practice

Synchronous generators and per-unit quantities

Rotating fields, synchronous speed and consistent three-phase bases.

Third-year engineering · 90 minutes

Before you begin: complex numbers, three-phase circuits and rotational mechanics.

After this lesson you can: relate frequency to rotor speed and convert voltage, current and reactance to per unit.

Work through the explanation, examples, practical experiment and independent exercises.

From rotation to electrical frequency

The rotor field rotates relative to the three-phase stator winding. With p pole pairs, one mechanical revolution produces p electrical cycles. In synchronous operation the generated EMF has the grid frequency; a temporary speed deviation changes rotor angle relative to the grid.

ns = 60f/p [rpm]; ωs,mechanical = 2πf/p [rad/s]
δelectrical = p·δmechanical

At 50 Hz, a two-pole machine runs at 3000 rpm and a four-pole machine at 1500 rpm. Electrical load angle is not the absolute shaft position.

Consistent bases

Choose total three-phase apparent-power base Sb and RMS line-to-line voltage base Ub. For a balanced system, the per-unit single-phase equivalent then needs no extra factor of three in its power formulas.

Ib = Sb/(√3 Ub); Zb = Ub²/Sb
u = U/Ub; i = I/Ib; x = X/Zb; Ppu = P/Sb

At 100 MVA and 10.5 kV, Ib = 5.499 kA and Zb = 1.1025 Ω. A reactance of 0.6 pu is 0.6615 Ω. Power of 0.8 pu means 80 MW here, not a power factor of 0.8.

Changing bases

xnew = xold · (Snew/Sold) · (Uold/Unew)²

Refer generator, transformer and line reactances to consistent bases before adding them. In the laboratory, X is the total reactance between internal EMF and grid bus. Changing only Sb and Ub in the form changes the physical scale while keeping per-unit parameters fixed; it represents another physical system with the same normalized dynamics.

Independent exercises

1. Find the speed of a six-pole machine at 50 Hz.

Show solution

p = 3, so ns = 1000 rpm.

2. Transfer x = 0.2 from 50 MVA to 100 MVA at unchanged voltage base.

Show solution

xnew = 0.4 pu. The physical reactance is unchanged.

Practical work

Record the current base at 100 MVA and 10.5 kV. Double Sb without changing the other form fields: per-unit traces remain identical while current in kA doubles. Explain the physical scaling.

Key takeaways

Power and line-voltage bases determine current and impedance bases. Electrical angle is mechanical angle multiplied by the number of pole pairs.

Open the generator model →

Progress is stored only in this browser.